第
2 页
230.72
>
-0.013
<
L/6=
325.04 kpa
325.70 kpa
3000
=
3000
b=
3600
>
hc+2*Ho=
2040
L=
3600
>
2040
2199600
2040 mm
1320 mm
760.42
>
2199600
2040 mm
1320 mm
760.42
>
1463.63
<
1463.63
<
325.04 kpa
312.13 kpa
319.66 kpa
MIx=(b-hc)^2*[(2*L+bc)*(pmaxX+pX-2*G/A)+(pmaxX-pX)*L]/48=
MⅡx=(L-bc)^2*(2*b+hc)*(pmaxX+pminX-2*G/A)/48=
325.70 kpa
311.47 kpa
319.77 kpa
MIy=(b-hc)^2*[(2*L+bc)*(pmaxY+pY-2*G/A)+(pmaxY-pY)*L]/48=
MⅡy=(L-bc)^2*(2*b+hc)*(pmaxY+pminY-2*G/A)/48=
788.56 kN·M
1127 mm^2/M
Φ
790.06 kN·M
1129 mm^2/M
Φ
柱下局部受压承载力计算
360000 mm^2
490000 mm^2
1.17
6747.30
>
F =
Y向pkminY=(Fk+Gk)/A-|Mkx|/Wy=
Y向偏心矩
ey=Mkx/(Fk+Gk)=
pmaxX=γz*PkmaxX=
pjmaxX=pmaxX-G/A=
pmaxY=γz*PkmaxY=
pjmaxY=pmaxY-G/A=
X方向冲切验算
因b
- hc=
L
- bc=
b
c+2*Ho=
Alx=0.5*(b-hc+2*bc+2*Ho)*[(b-hc)/2-Ho]=
ab
=
Min{bc + 2 * Ho,l} =
amx
=
(bc + ab) / 2 =
0.7 * βhp * ft * amx * Ho =
Flx=pjmaxX*Alx
Y方向冲切验算
Aly=0.5*(l-bc+2*hc+2*Ho)*[(l-bc)/2-Ho]=
ab
=
Min{hc + 2 * Ho,b}
amy
=
(hc + ab) / 2
0.7 * βhp * ft * amY * Ho =
Fly=pjmaxY*Aly
X 方向(b 方向)剪切验算
计算宽度
Lo={1.0-0.5*[1.0-(bc+2*50)/L]*(Ho-h1)/Ho}*L=
Vx=pj*Ax=pj*(b-hc)*L/2=
0.7*βh*ft*Lo*Ho
Y 方向(l 方向)剪切验算
计算宽度
bo={1.0-0.5*[1.0-(hc+2*50)/b]*(Ho-h1)/Ho}*b=
Vy=pj*Ay=pj*(l-bc)*b/2=
0.7*βh*ft*bo*Ho
X 方向(b 方向)柱边(绕 Y 轴)抗弯计算
pmaxX=γz*PkmaxX=
pminX=γz*PkminX=
pX=pminX+(pmaxX-pminX)*(b+hc)/b/2=
Y 方向(l
方向)柱边(绕
X 轴)抗弯计算
pmaxY=γz*PkmaxY=
pminY=γz*PkminY=
pY=pminY+(pmaxY-pminY)*(L+bc)/L/2=
M
Ⅰ = Max{MⅠx,MⅡy} =
As
Ⅰ=MⅠ/0.9*h0*fy*L=
M
Ⅱ = Max{MⅡx,MⅠy} =
As
Ⅱ=MⅡ/0.9*h0*fy*B=
混凝土局部受压面积
Al
=
bc * hc =
Ab
=
(bx + 2 * c) * (by + 2 * c)=
βl
=
Sqr(Ab / Al)=
1.35
* βc * βl * fc * Al =