max

0

q

=

]

)

(

8

.

0

)

(

2

.

0

1

[

2

0

r

wf

r

wf

p

p

p

p

q

−

−

      =

)

(

64

]

)

16

12

(

8

.

0

)

16

12

(

2

.

0

1

[

6

.

25

3

2

d

m

=

−

−

②当

MPa

p

wf

8

=

时

]

)

(

8

.

0

)

(

2

.

0

1

[

2

max

0

0

r

wf

r

wf

p

p

p

p

q

q

−

−

=

=64

d

m

3

2

8

.

44

]

)

16

8

(

8

.

0

)

16

8

(

2

.

0

1

[

=

−

−

×

      ③为绘制 IPR 曲线。计算了不同

wf

p

的产量，见表

产量

57.6

44.8

25.6

64

0

流压

4

8

12

0

16

0

4

8

12

16

0

10

20

30

40

50

60

70

3.已知某井

,

14MPa

p

r

=

.

b

r

p

p

〈

当

MPa

p

wf

11

=

,产量为

,

7

.

0

,

30

3

0

=

=

FE

d

m

q

试计算:

  ①

0

.

1

max

0

=

FE

q

②

7

.

0

max

0

=

FE

q

③当

时的产量。

和

，

而

2

.

1

0

.

1

7

.

0

9

=

=

FE

MPa

p

wf

解: ①

MPa

FE

p

p

p

p

wf

r

r

wf

9

.

11

7

.

0

)

11

14

(

14

)

(

=

×

−

−

=

⋅

−

−

=

′

    由

=

=

0

.

1

max

0

0

FE

q

q

2

)

(

8

.

0

)

(

2

.

0

1

r

wf

r

wf

p

P

p

P

′

−

′

−

得

    

/

0

0

.

1

max

0

q

q

FE

=

=

[

2

)

(

8

.

0

)

(

2

.

0

1

r

wf

r

wf

p

P

p

P

′

−

′

−

]

          

d

m

3

2

119

]

)

14

9

.

11

(

8

.

0

)

14

9

.

11

(

2

.

0

1

[

30

=

−

−

=

②当

时，

0

=

wf

p

MPa

FE

p

p

p

p

wf

r

r

wf

2

.

4

7

.

0

)

0

14

(

14

)

(

=

×

−

−

=

⋅

−

−

=

′

2